simpler, faster color code

main
Fabien Benureau 12 years ago
parent fed60b7069
commit f1bf98cd52

@ -1,60 +1,24 @@
# display
BOLD = '\033[1m'
END = '\033[0m'
COLORS = {
'black' : '\033[0;30m',
'red' : '\033[0;31m',
'green' : '\033[0;32m',
'yellow': '\033[0;33m',
'blue' : '\033[0;34m',
'purple': '\033[0;35m',
'cyan' : '\033[0;36m',
'grey' : '\032[0;37m',
}
# Bold
BCOLORS = {
'black' : '\033[1;30m',
'red' : '\033[1;31m',
'green' : '\033[1;32m',
'yellow': '\033[1;33m',
'blue' : '\033[1;34m',
'purple': '\033[1;35m',
'cyan' : '\033[1;36m',
'grey' : '\033[1;37m',
}
# application specific
ALIASES = {
'ok' : 'green',
'error' : 'red',
'normal' : 'grey',
'citekey' : 'purple',
'filepath': 'cyan',
}
def colored(s, color=None, bold=False):
if color in ALIASES:
color = ALIASES[color]
try:
if bold:
color_code = BCOLORS[color]
else:
color_code = COLORS[color]
except KeyError:
if bold:
color_code = BOLD
else:
color_code = ''
if color_code != '':
end_code = END
else:
end_code = ''
return color_code + s + end_code
def not_colored(s, **kwargs):
return s
bold = '\033[1m'
end = '\033[0m'
black = '\033[0;30m'
red = '\033[0;31m'
green = '\033[0;32m'
yellow = '\033[0;33m'
blue = '\033[0;34m'
purple = '\033[0;35m'
cyan = '\033[0;36m'
grey = '\033[0;37m'
ok = green
error = red
normal = grey
citekey = purple
filepath = cyan
def colored(s, color=end, bold=False):
if bold:
s = '\033[1' + s[3:]
return color + s + end

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